![]() One way to find the vertex of a quadratic function thatis in polynomial form is to use the formula to find the 2 -coordinate of the vertex. Y=-(x-4)^2 + 4 has 2 zeros, x= 6 and x= 2, or (6,0) and (2,0)Įither x value makes y=0. So then then, the standard form of a quadratic function y a ( x h ) 2 + k y a(x-h)2 + k ya(xh)2+k is the same as the vertex form. However when a quadratic function is expressed in polynomial form (()2++), the vertex of the quadratic function is not obvious. You could say it really as 2 zeros, but the two zeros are identical, both the same point. ![]() ![]() whenever the multiplicity is 2, the curve doesn't intersect the x axis, but just touches it. If the quadratic is written in the form y a(x h)2 + k, then the vertex is the. This vertex will either be the maximum or minimum point on the graph. Although it has only one zero, its a zero with multiplicity 2. This point, where the parabola changes direction, is called the vertex. The point where a parabola meets its axis of symmetry is called the vertex. ![]() the x intercept or zero is the vertex = (0,0) It's in vertex form with y=-(x-0)^2 + 0 where vertex is (0,0) which is the maximum point of the parabola. Y=-x^2 has one zero, the origin (0,0) the x^2 term has to have a negative coefficient to open downward. ![]()
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